tags: leetcode
Tips:
- dfs with reverting the two node (left and right).
- Remember to return the node.
Code
class Solution:
def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
if root == None:
return
root.left, root.right = root.right, root.left
self.invertTree(root.left)
self.invertTree(root.right)
return root